Question
Factor the expression
3c3(1−c)(1−3c)
Evaluate
3c3−12c4+9c5
Rewrite the expression
3c3−3c3×4c+3c3×3c2
Factor out 3c3 from the expression
3c3(1−4c+3c2)
Solution
More Steps

Evaluate
1−4c+3c2
Rewrite the expression
1+(−3−1)c+3c2
Calculate
1−3c−c+3c2
Rewrite the expression
1−3c−c+c×3c
Factor out −c from the expression
1−3c−c(1−3c)
Factor out 1−3c from the expression
(1−c)(1−3c)
3c3(1−c)(1−3c)
Show Solution

Find the roots
c1=0,c2=31,c3=1
Alternative Form
c1=0,c2=0.3˙,c3=1
Evaluate
3c3−12c4+9c5
To find the roots of the expression,set the expression equal to 0
3c3−12c4+9c5=0
Factor the expression
3c3(1−c)(1−3c)=0
Divide both sides
c3(1−c)(1−3c)=0
Separate the equation into 3 possible cases
c3=01−c=01−3c=0
The only way a power can be 0 is when the base equals 0
c=01−c=01−3c=0
Solve the equation
More Steps

Evaluate
1−c=0
Move the constant to the right-hand side and change its sign
−c=0−1
Removing 0 doesn't change the value,so remove it from the expression
−c=−1
Change the signs on both sides of the equation
c=1
c=0c=11−3c=0
Solve the equation
More Steps

Evaluate
1−3c=0
Move the constant to the right-hand side and change its sign
−3c=0−1
Removing 0 doesn't change the value,so remove it from the expression
−3c=−1
Change the signs on both sides of the equation
3c=1
Divide both sides
33c=31
Divide the numbers
c=31
c=0c=1c=31
Solution
c1=0,c2=31,c3=1
Alternative Form
c1=0,c2=0.3˙,c3=1
Show Solution
