Question
Solve the equation
k1=−26,k2=0,k3=26
Alternative Form
k1≈−1.224745,k2=0,k3≈1.224745
Evaluate
3k2−2k4=0
Factor the expression
k2(3−2k2)=0
Separate the equation into 2 possible cases
k2=03−2k2=0
The only way a power can be 0 is when the base equals 0
k=03−2k2=0
Solve the equation
More Steps

Evaluate
3−2k2=0
Move the constant to the right-hand side and change its sign
−2k2=0−3
Removing 0 doesn't change the value,so remove it from the expression
−2k2=−3
Change the signs on both sides of the equation
2k2=3
Divide both sides
22k2=23
Divide the numbers
k2=23
Take the root of both sides of the equation and remember to use both positive and negative roots
k=±23
Simplify the expression
More Steps

Evaluate
23
To take a root of a fraction,take the root of the numerator and denominator separately
23
Multiply by the Conjugate
2×23×2
Multiply the numbers
2×26
When a square root of an expression is multiplied by itself,the result is that expression
26
k=±26
Separate the equation into 2 possible cases
k=26k=−26
k=0k=26k=−26
Solution
k1=−26,k2=0,k3=26
Alternative Form
k1≈−1.224745,k2=0,k3≈1.224745
Show Solution
