Algebra
Calculus
Trigonometry
Matrix
Question
Solve the inequality
x>e5+2
Alternative Form
x∈(e5+2,+∞)
Evaluate
3ln(x−2)>15
Find the domain
More Steps
Evaluate
x−2>0
Move the constant to the right side
x>0+2
Removing 0 doesn't change the value,so remove it from the expression
x>2
3ln(x−2)>15,x>2
Divide both sides
33ln(x−2)>315
Divide the numbers
ln(x−2)>315
Divide the numbers
More Steps
Evaluate
315
Reduce the numbers
15
Calculate
5
ln(x−2)>5
For e>1 the expression ln(x−2)>5 is equivalent to x−2>e5
x−2>e5
Move the constant to the right side
x>e5+2
Check if the solution is in the defined range
x>e5+2,x>2
Solution
x>e5+2
Alternative Form
x∈(e5+2,+∞)
Show Solution
