Question
Factor the expression
3(t−1)(t+1)
Evaluate
3t2−3
Factor out 3 from the expression
3(t2−1)
Solution
More Steps

Evaluate
t2−1
Rewrite the expression in exponential form
t2−12
Use a2−b2=(a−b)(a+b) to factor the expression
(t−1)(t+1)
3(t−1)(t+1)
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Find the roots
t1=−1,t2=1
Evaluate
3t2−3
To find the roots of the expression,set the expression equal to 0
3t2−3=0
Move the constant to the right-hand side and change its sign
3t2=0+3
Removing 0 doesn't change the value,so remove it from the expression
3t2=3
Divide both sides
33t2=33
Divide the numbers
t2=33
Divide the numbers
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Evaluate
33
Reduce the numbers
11
Calculate
1
t2=1
Take the root of both sides of the equation and remember to use both positive and negative roots
t=±1
Simplify the expression
t=±1
Separate the equation into 2 possible cases
t=1t=−1
Solution
t1=−1,t2=1
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