Solve 3x^2 - 7x^29 = (x^4)^2

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Type your math problem... 3x^2 - 7x^29 = (x^4)^2

Question

Solve the equation

x = 0

Evaluate

3 x^{2} - 7 x^{2} \times 9 = (x^{4})^{2}

Simplify

More Steps

Evaluate

3 x^{2} - 7 x^{2} \times 9

Multiply the terms

3 x^{2} - 63 x^{2}

Collect like terms by calculating the sum or difference of their coefficients

(3 - 63) x^{2}

Subtract the numbers

- 60 x^{2}

- 60 x^{2} = (x^{4})^{2}

Simplify

More Steps

Evaluate

(x^{4})^{2}

Multiply the exponents

x^{4 \times 2}

Multiply the numbers

x^{8}

- 60 x^{2} = x^{8}

The statement is true only if both sides equal 0

{- 60 x^{2} = 0 x^{8} = 0

Solve the equation

More Steps

Evaluate

- 60 x^{2} = 0

Change the signs on both sides of the equation

60 x^{2} = 0

Rewrite the expression

x^{2} = 0

The only way a power can be 0 is when the base equals 0

x = 0

{x = 0 x^{8} = 0

The only way a power can be 0 is when the base equals 0

{x = 0 x = 0

Solution

x = 0

Show Solution

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