Solve 3x^2-2x-10 - ScanMath

Question

Find the roots

x_{1} = \frac{1 - 31}{3}, x_{2} = \frac{1 + 31}{3}

Alternative Form

x_{1} \approx - 1.522588, x_{2} \approx 2.189255

Evaluate

3 x^{2} - 2 x - 10

To find the roots of the expression,set the expression equal to 0

3 x^{2} - 2 x - 10 = 0

Substitute a= 3,b= - 2 and c= - 10 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{2 \pm ( - 2 ) ^{2} - 4 \times 3 ( - 10 )}{2 \times 3}

Simplify the expression

x = \frac{2 \pm ( - 2 ) ^{2} - 4 \times 3 ( - 10 )}{6}

Simplify the expression

More Steps

x = \frac{2 \pm 124}{6}

Simplify the radical expression

More Steps

x = \frac{2 \pm 2 31}{6}

Separate the equation into 2 possible cases

x = \frac{2 + 2 31}{6} x = \frac{2 - 2 31}{6}

Simplify the expression

More Steps

x = \frac{1 + 31}{3} x = \frac{2 - 2 31}{6}

Simplify the expression

More Steps

x = \frac{1 + 31}{3} x = \frac{1 - 31}{3}

Solution

x_{1} = \frac{1 - 31}{3}, x_{2} = \frac{1 + 31}{3}

Alternative Form

x_{1} \approx - 1.522588, x_{2} \approx 2.189255

Show Solution