Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x∈(−∞,0)∪(1,+∞)
Evaluate
3x6−x>2x2
Move the expression to the left side
3x6−x−2x2>0
Rewrite the expression
3x6−x−2x2=0
Factor the expression
x(x−1)(3x4+3x3+3x2+3x+1)=0
Separate the equation into 3 possible cases
x=0x−1=03x4+3x3+3x2+3x+1=0
Solve the equation
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Evaluate
x−1=0
Move the constant to the right-hand side and change its sign
x=0+1
Removing 0 doesn't change the value,so remove it from the expression
x=1
x=0x=13x4+3x3+3x2+3x+1=0
Solve the equation
x=0x=1x∈/R
Find the union
x=0x=1
Determine the test intervals using the critical values
x<00<x<1x>1
Choose a value form each interval
x1=−1x2=21x3=2
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
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Evaluate
3(−1)6−(−1)>2(−1)2
Simplify
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Evaluate
3(−1)6−(−1)
Evaluate the power
3×1−(−1)
Any expression multiplied by 1 remains the same
3−(−1)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
3+1
Add the numbers
4
4>2(−1)2
Simplify
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Evaluate
2(−1)2
Evaluate the power
2×1
Any expression multiplied by 1 remains the same
2
4>2
Check the inequality
true
x<0 is the solutionx2=21x3=2
To determine if 0<x<1 is the solution to the inequality,test if the chosen value x=21 satisfies the initial inequality
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Evaluate
3(21)6−21>2(21)2
Simplify
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Evaluate
3(21)6−21
Multiply the terms
643−21
Reduce fractions to a common denominator
643−2×3232
Multiply the numbers
643−6432
Write all numerators above the common denominator
643−32
Subtract the numbers
64−29
Use b−a=−ba=−ba to rewrite the fraction
−6429
−6429>2(21)2
Multiply the terms
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Evaluate
2(21)2
Rewrite the expression
(21)−1(21)2
Rewrite the expression
(21)−1+2
Calculate
(21)1
Calculate
21
−6429>21
Calculate
−0.453125>21
Calculate
−0.453125>0.5
Check the inequality
false
x<0 is the solution0<x<1 is not a solutionx3=2
To determine if x>1 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
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Evaluate
3×26−2>2×22
Simplify
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Evaluate
3×26−2
Multiply the terms
192−2
Subtract the numbers
190
190>2×22
Calculate the product
190>23
Calculate
190>8
Check the inequality
true
x<0 is the solution0<x<1 is not a solutionx>1 is the solution
Solution
x∈(−∞,0)∪(1,+∞)
Show Solution
