Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
3y2−5y3
Evaluate
3y2−y×5y2
Solution
More Steps
Evaluate
y×5y2
Use the commutative property to reorder the terms
5y×y2
Multiply the terms
More Steps
Evaluate
y×y2
Use the product rule an×am=an+m to simplify the expression
y1+2
Add the numbers
y3
5y3
3y2−5y3
Show Solution
Factor the expression
y2(3−5y)
Evaluate
3y2−y×5y2
Multiply the terms
More Steps
Evaluate
y×5y2
Use the commutative property to reorder the terms
5y×y2
Multiply the terms
More Steps
Evaluate
y×y2
Use the product rule an×am=an+m to simplify the expression
y1+2
Add the numbers
y3
5y3
3y2−5y3
Rewrite the expression
y2×3−y2×5y
Solution
y2(3−5y)
Show Solution
Find the roots
y1=0,y2=53
Alternative Form
y1=0,y2=0.6
Evaluate
3y2−y(5y2)
To find the roots of the expression,set the expression equal to 0
3y2−y(5y2)=0
Multiply the terms
3y2−y×5y2=0
Multiply the terms
More Steps
Evaluate
y×5y2
Use the commutative property to reorder the terms
5y×y2
Multiply the terms
More Steps
Evaluate
y×y2
Use the product rule an×am=an+m to simplify the expression
y1+2
Add the numbers
y3
5y3
3y2−5y3=0
Factor the expression
y2(3−5y)=0
Separate the equation into 2 possible cases
y2=03−5y=0
The only way a power can be 0 is when the base equals 0
y=03−5y=0
Solve the equation
More Steps
Evaluate
3−5y=0
Move the constant to the right-hand side and change its sign
−5y=0−3
Removing 0 doesn't change the value,so remove it from the expression
−5y=−3
Change the signs on both sides of the equation
5y=3
Divide both sides
55y=53
Divide the numbers
y=53
y=0y=53
Solution
y1=0,y2=53
Alternative Form
y1=0,y2=0.6
Show Solution