Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
3y(y−10)(y+10)
Evaluate
3y3−300y
Factor out 3y from the expression
3y(y2−100)
Solution
More Steps
Evaluate
y2−100
Rewrite the expression in exponential form
y2−102
Use a2−b2=(a−b)(a+b) to factor the expression
(y−10)(y+10)
3y(y−10)(y+10)
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Find the roots
y1=−10,y2=0,y3=10
Evaluate
3y3−300y
To find the roots of the expression,set the expression equal to 0
3y3−300y=0
Factor the expression
3y(y2−100)=0
Divide both sides
y(y2−100)=0
Separate the equation into 2 possible cases
y=0y2−100=0
Solve the equation
More Steps
Evaluate
y2−100=0
Move the constant to the right-hand side and change its sign
y2=0+100
Removing 0 doesn't change the value,so remove it from the expression
y2=100
Take the root of both sides of the equation and remember to use both positive and negative roots
y=±100
Simplify the expression
More Steps
Evaluate
100
Write the number in exponential form with the base of 10
102
Reduce the index of the radical and exponent with 2
10
y=±10
Separate the equation into 2 possible cases
y=10y=−10
y=0y=10y=−10
Solution
y1=−10,y2=0,y3=10
Show Solution