Solve 4/5=sinb - ScanMath

Evaluate

\frac{4}{5} = sin (b)

Swap the sides of the equation

sin (b) = \frac{4}{5}

Use the inverse trigonometric function

b = arcsin (\frac{4}{5})

Calculate

b = arcsin (\frac{4}{5}) b = - arcsin (\frac{4}{5}) + π

Add the period of 2 kπ, k \in Z to find all solutions

b = arcsin (\frac{4}{5}) + 2 kπ, k \in Z b = - arcsin (\frac{4}{5}) + π + 2 kπ, k \in Z

Solution

b = {arcsin (\frac{4}{5}) + 2 kπ - arcsin (\frac{4}{5}) + π + 2 kπ, k \in Z

Alternative Form

b \approx {53.13010 2^{\circ} + 36 0^{\circ} k 126.86989 8^{\circ} + 36 0^{\circ} k, k \in Z

Alternative Form

b \approx {0.927295 + 2 kπ 2.214297 + 2 kπ, k \in Z

Solve the equation