Solve 4(v-1) v=3(v-2) 2

Question

Solve the equation(The real numbers system)

v \in / R

Alternative Form

No real solution

Show Solution

Solve using the quadratic formula in the complex numbers system

Solve by completing the square in the complex numbers system

Solve using the PQ formula in the complex numbers system

v_{1} = \frac{5}{4} - \frac{23}{4} i, v_{2} = \frac{5}{4} + \frac{23}{4} i

Alternative Form

v_{1} \approx 1.25 - 1.198958 i, v_{2} \approx 1.25 + 1.198958 i

Evaluate

4 (v - 1) v = 3 (v - 2) \times 2

Multiply the terms

4 v (v - 1) = 3 (v - 2) \times 2

Multiply the terms

4 v (v - 1) = 6 (v - 2)

Expand the expression

More Steps

4 v^{2} - 4 v = 6 (v - 2)

Expand the expression

More Steps

4 v^{2} - 4 v = 6 v - 12

Move the expression to the left side

4 v^{2} - 10 v + 12 = 0

Substitute a= 4,b= - 10 and c= 12 into the quadratic formula v = \frac{- b \pm b ^{2} - 4 a c}{2 a}

v = \frac{10 \pm ( - 10 ) ^{2} - 4 \times 4 \times 12}{2 \times 4}

Simplify the expression

v = \frac{10 \pm ( - 10 ) ^{2} - 4 \times 4 \times 12}{8}

Simplify the expression

More Steps

v = \frac{10 \pm - 92}{8}

Simplify the radical expression

More Steps

v = \frac{10 \pm 2 23 \times i}{8}

Separate the equation into 2 possible cases

v = \frac{10 + 2 23 \times i}{8} v = \frac{10 - 2 23 \times i}{8}

Simplify the expression

More Steps

v = \frac{5}{4} + \frac{23}{4} i v = \frac{10 - 2 23 \times i}{8}

Simplify the expression

More Steps

v = \frac{5}{4} + \frac{23}{4} i v = \frac{5}{4} - \frac{23}{4} i

Solution

v_{1} = \frac{5}{4} - \frac{23}{4} i, v_{2} = \frac{5}{4} + \frac{23}{4} i

Alternative Form

v_{1} \approx 1.25 - 1.198958 i, v_{2} \approx 1.25 + 1.198958 i

Show Solution