Solve 4-12c=14(3-c) 18c - ScanMath

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Type your math problem... 4-12c=14(3-c) 18c

Question

Solve the quadratic equation

Solve using the quadratic formula

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Solve by completing the square

Solve using the PQ formula

c_{1} = \frac{32 - 3 113}{21}, c_{2} = \frac{32 + 3 113}{21}

Alternative Form

c_{1} \approx 0.005217, c_{2} \approx 3.042402

Evaluate

4 - 12 c = 14 (3 - c) \times 18 c

Multiply

More Steps

4 - 12 c = 252 c (3 - c)

Swap the sides

252 c (3 - c) = 4 - 12 c

Expand the expression

More Steps

756 c - 252 c^{2} = 4 - 12 c

Move the expression to the left side

768 c - 252 c^{2} - 4 = 0

Rewrite in standard form

- 252 c^{2} + 768 c - 4 = 0

Multiply both sides

252 c^{2} - 768 c + 4 = 0

Substitute a= 252,b= - 768 and c= 4 into the quadratic formula c = \frac{- b \pm b ^{2} - 4 a c}{2 a}

c = \frac{768 \pm ( - 768 ) ^{2} - 4 \times 252 \times 4}{2 \times 252}

Simplify the expression

c = \frac{768 \pm ( - 768 ) ^{2} - 4 \times 252 \times 4}{504}

Simplify the expression

More Steps

c = \frac{768 \pm 76 8 ^{2} - 4032}{504}

Simplify the radical expression

More Steps

c = \frac{768 \pm 72 113}{504}

Separate the equation into 2 possible cases

c = \frac{768 + 72 113}{504} c = \frac{768 - 72 113}{504}

Simplify the expression

More Steps

c = \frac{32 + 3 113}{21} c = \frac{768 - 72 113}{504}

Simplify the expression

More Steps

c = \frac{32 + 3 113}{21} c = \frac{32 - 3 113}{21}

Solution

c_{1} = \frac{32 - 3 113}{21}, c_{2} = \frac{32 + 3 113}{21}

Alternative Form

c_{1} \approx 0.005217, c_{2} \approx 3.042402

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