Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve for f
−26480<f<26480
Alternative Form
f∈(−26480,26480)
Evaluate
4f6<30
Move the expression to the left side
4f6−30<0
Rewrite the expression
4f6−30=0
Move the constant to the right-hand side and change its sign
4f6=0+30
Removing 0 doesn't change the value,so remove it from the expression
4f6=30
Divide both sides
44f6=430
Divide the numbers
f6=430
Cancel out the common factor 2
f6=215
Take the root of both sides of the equation and remember to use both positive and negative roots
f=±6215
Simplify the expression
More Steps

Evaluate
6215
To take a root of a fraction,take the root of the numerator and denominator separately
62615
Multiply by the Conjugate
62×625615×625
Simplify
62×625615×632
Multiply the numbers
More Steps

Evaluate
615×632
The product of roots with the same index is equal to the root of the product
615×32
Calculate the product
6480
62×6256480
Multiply the numbers
More Steps

Evaluate
62×625
The product of roots with the same index is equal to the root of the product
62×25
Calculate the product
626
Reduce the index of the radical and exponent with 6
2
26480
f=±26480
Separate the equation into 2 possible cases
f=26480f=−26480
Determine the test intervals using the critical values
f<−26480−26480<f<26480f>26480
Choose a value form each interval
f1=−2f2=0f3=2
To determine if f<−26480 is the solution to the inequality,test if the chosen value f=−2 satisfies the initial inequality
More Steps

Evaluate
4(−2)6<30
Multiply the terms
More Steps

Evaluate
4(−2)6
Evaluate the power
4×64
Multiply the numbers
256
256<30
Check the inequality
false
f<−26480 is not a solutionf2=0f3=2
To determine if −26480<f<26480 is the solution to the inequality,test if the chosen value f=0 satisfies the initial inequality
More Steps

Evaluate
4×06<30
Simplify
More Steps

Evaluate
4×06
Calculate
4×0
Any expression multiplied by 0 equals 0
0
0<30
Check the inequality
true
f<−26480 is not a solution−26480<f<26480 is the solutionf3=2
To determine if f>26480 is the solution to the inequality,test if the chosen value f=2 satisfies the initial inequality
More Steps

Evaluate
4×26<30
Multiply the terms
More Steps

Evaluate
4×26
Rewrite the expression
22×26
Rewrite the expression
22+6
Calculate
28
28<30
Calculate
256<30
Check the inequality
false
f<−26480 is not a solution−26480<f<26480 is the solutionf>26480 is not a solution
Solution
−26480<f<26480
Alternative Form
f∈(−26480,26480)
Show Solution
