Question
Factor the expression
4k2(1−3k3)
Evaluate
4k2−12k5
Rewrite the expression
4k2−4k2×3k3
Solution
4k2(1−3k3)
Show Solution

Find the roots
k1=0,k2=339
Alternative Form
k1=0,k2≈0.693361
Evaluate
4k2−12k5
To find the roots of the expression,set the expression equal to 0
4k2−12k5=0
Factor the expression
4k2(1−3k3)=0
Divide both sides
k2(1−3k3)=0
Separate the equation into 2 possible cases
k2=01−3k3=0
The only way a power can be 0 is when the base equals 0
k=01−3k3=0
Solve the equation
More Steps

Evaluate
1−3k3=0
Move the constant to the right-hand side and change its sign
−3k3=0−1
Removing 0 doesn't change the value,so remove it from the expression
−3k3=−1
Change the signs on both sides of the equation
3k3=1
Divide both sides
33k3=31
Divide the numbers
k3=31
Take the 3-th root on both sides of the equation
3k3=331
Calculate
k=331
Simplify the root
More Steps

Evaluate
331
To take a root of a fraction,take the root of the numerator and denominator separately
3331
Simplify the radical expression
331
Multiply by the Conjugate
33×332332
Simplify
33×33239
Multiply the numbers
339
k=339
k=0k=339
Solution
k1=0,k2=339
Alternative Form
k1=0,k2≈0.693361
Show Solution
