Solve 4t^2+30t-300=0

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

t_{1} = - \frac{15 + 5 57}{4}, t_{2} = \frac{- 15 + 5 57}{4}

Alternative Form

t_{1} \approx - 13.187293, t_{2} \approx 5.687293

Evaluate

4 t^{2} + 30 t - 300 = 0

Substitute a= 4,b= 30 and c= - 300 into the quadratic formula t = \frac{- b \pm b ^{2} - 4 a c}{2 a}

t = \frac{- 30 \pm 3 0 ^{2} - 4 \times 4 ( - 300 )}{2 \times 4}

Simplify the expression

t = \frac{- 30 \pm 3 0 ^{2} - 4 \times 4 ( - 300 )}{8}

Simplify the expression

More Steps

t = \frac{- 30 \pm 5700}{8}

Simplify the radical expression

More Steps

t = \frac{- 30 \pm 10 57}{8}

Separate the equation into 2 possible cases

t = \frac{- 30 + 10 57}{8} t = \frac{- 30 - 10 57}{8}

Simplify the expression

More Steps

t = \frac{- 15 + 5 57}{4} t = \frac{- 30 - 10 57}{8}

Simplify the expression

More Steps

t = \frac{- 15 + 5 57}{4} t = - \frac{15 + 5 57}{4}

Solution

t_{1} = - \frac{15 + 5 57}{4}, t_{2} = \frac{- 15 + 5 57}{4}

Alternative Form

t_{1} \approx - 13.187293, t_{2} \approx 5.687293

Show Solution