Question
Solve the equation
v1=−29249×2923,v2=29249×2923
Alternative Form
v1≈−0.419001,v2≈0.419001
Evaluate
4v3×73v=9
Multiply
More Steps

Evaluate
4v3×73v
Multiply the terms
292v3×v
Multiply the terms with the same base by adding their exponents
292v3+1
Add the numbers
292v4
292v4=9
Divide both sides
292292v4=2929
Divide the numbers
v4=2929
Take the root of both sides of the equation and remember to use both positive and negative roots
v=±42929
Simplify the expression
More Steps

Evaluate
42929
To take a root of a fraction,take the root of the numerator and denominator separately
429249
Simplify the radical expression
More Steps

Evaluate
49
Write the number in exponential form with the base of 3
432
Reduce the index of the radical and exponent with 2
3
42923
Multiply by the Conjugate
4292×429233×42923
Multiply the numbers
More Steps

Evaluate
3×42923
Use na=mnam to expand the expression
432×42923
The product of roots with the same index is equal to the root of the product
432×2923
Calculate the product
49×2923
4292×4292349×2923
Multiply the numbers
More Steps

Evaluate
4292×42923
The product of roots with the same index is equal to the root of the product
4292×2923
Calculate the product
42924
Reduce the index of the radical and exponent with 4
292
29249×2923
v=±29249×2923
Separate the equation into 2 possible cases
v=29249×2923v=−29249×2923
Solution
v1=−29249×2923,v2=29249×2923
Alternative Form
v1≈−0.419001,v2≈0.419001
Show Solution
