Question
Solve the inequality
x∈R
Alternative Form
All real solution
Evaluate
4x+6>1−x3(x−1)≤x+5
Separate into two inequalities
{4x+6>1−x3(x−1)1−x3(x−1)≤x+5
Solve the inequality
More Steps

Evaluate
4x+6>1−x3(x−1)
Move the expression to the left side
4x+6−(1−x3(x−1))>0
Calculate the sum or difference
More Steps

Evaluate
4x+6−(1−x3(x−1))
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
4x+6−1+x3(x−1)
Subtract the numbers
4x+5+x3(x−1)
4x+5+x3(x−1)>0
Calculate
More Steps

Evaluate
x3(x−1)
Apply the distributive property
x3×x−x3×1
Multiply the terms
x4−x3×1
Any expression multiplied by 1 remains the same
x4−x3
4x+5+x4−x3>0
Rewrite the expression
4x+5+x4−x3=0
Find the critical values by solving the corresponding equation
x∈/R
There are no key numbers,so choose any value to test,for example x=0
x=0
To determine if the solution to the inequality are all real numbers,test if the chosen value satisfies the initial inequality
More Steps

Evaluate
4×0+5+04−03>0
Any expression multiplied by 0 equals 0
0+5+04−03>0
Simplify
5>0
Check the inequality
true
x∈R
{x∈R1−x3(x−1)≤x+5
Solve the inequality
More Steps

Evaluate
1−x3(x−1)≤x+5
Move the expression to the left side
1−x3(x−1)−(x+5)≤0
Subtract the terms
More Steps

Evaluate
1−x3(x−1)−(x+5)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
1−x3(x−1)−x−5
Subtract the numbers
−4−x3(x−1)−x
−4−x3(x−1)−x≤0
Calculate
More Steps

Evaluate
−x3(x−1)
Apply the distributive property
−x3×x−(−x3×1)
Multiply the terms
−x4−(−x3×1)
Any expression multiplied by 1 remains the same
−x4−(−x3)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−x4+x3
−4−x4+x3−x≤0
Rewrite the expression
−4−x4+x3−x=0
Find the critical values by solving the corresponding equation
x∈/R
There are no key numbers,so choose any value to test,for example x=0
x=0
To determine if the solution to the inequality are all real numbers,test if the chosen value satisfies the initial inequality
More Steps

Evaluate
−4−04+03−0≤0
Simplify
−4≤0
Check the inequality
true
x∈R
{x∈Rx∈R
Solution
x∈R
Alternative Form
All real solution
Show Solution
