Question Solve the quadratic equation Solve by factoring Solve using the quadratic formula Solve by completing the square Load more x1=−537,x2=0Alternative Form x1≈−0.132075,x2=0 Evaluate 4x2×53=−28xMultiply the terms 212x2=−28xMove the expression to the left side 212x2+28x=0Factor the expression More Steps Evaluate 212x2+28xRewrite the expression 4x×53x+4x×7Factor out 4x from the expression 4x(53x+7) 4x(53x+7)=0When the product of factors equals 0,at least one factor is 0 4x=053x+7=0Solve the equation for x x=053x+7=0Solve the equation for x More Steps Evaluate 53x+7=0Move the constant to the right-hand side and change its sign 53x=0−7Removing 0 doesn't change the value,so remove it from the expression 53x=−7Divide both sides 5353x=53−7Divide the numbers x=53−7Use b−a=−ba=−ba to rewrite the fraction x=−537 x=0x=−537Solution x1=−537,x2=0Alternative Form x1≈−0.132075,x2=0 Show Solution Graph