Solve 4x^6<=2 - ScanMath

Question

Solve the inequality

Solve the inequality by testing the values in the interval

Solve for x

- \frac{6 32}{2} \leq x \leq \frac{6 32}{2}

Alternative Form

x \in [- \frac{6 32}{2}, \frac{6 32}{2}]

Evaluate

4 x^{6} \leq 2

Move the expression to the left side

4 x^{6} - 2 \leq 0

Rewrite the expression

4 x^{6} - 2 = 0

Move the constant to the right-hand side and change its sign

4 x^{6} = 0 + 2

Removing 0 doesn't change the value,so remove it from the expression

4 x^{6} = 2

Divide both sides

\frac{4 x ^{6}}{4} = \frac{2}{4}

Divide the numbers

x^{6} = \frac{2}{4}

Cancel out the common factor 2

x^{6} = \frac{1}{2}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm 6 \frac{1}{2}

Simplify the expression

More Steps

x = \pm \frac{6 32}{2}

Separate the equation into 2 possible cases

x = \frac{6 32}{2} x = - \frac{6 32}{2}

Determine the test intervals using the critical values

x < - \frac{6 32}{2} - \frac{6 32}{2} < x < \frac{6 32}{2} x > \frac{6 32}{2}

Choose a value form each interval

x_{1} = - 2 x_{2} = 0 x_{3} = 2

To determine if x < - \frac{6 32}{2} is the solution to the inequality,test if the chosen value x = - 2 satisfies the initial inequality

More Steps

x < - \frac{6 32}{2} is not a solution x_{2} = 0 x_{3} = 2

To determine if - \frac{6 32}{2} < x < \frac{6 32}{2} is the solution to the inequality,test if the chosen value x = 0 satisfies the initial inequality

More Steps

x < - \frac{6 32}{2} is not a solution - \frac{6 32}{2} < x < \frac{6 32}{2} is the solution x_{3} = 2

To determine if x > \frac{6 32}{2} is the solution to the inequality,test if the chosen value x = 2 satisfies the initial inequality

More Steps

x < - \frac{6 32}{2} is not a solution - \frac{6 32}{2} < x < \frac{6 32}{2} is the solution x > \frac{6 32}{2} is not a solution

The original inequality is a nonstrict inequality,so include the critical value in the solution

- \frac{6 32}{2} \leq x \leq \frac{6 32}{2} is the solution

Solution

- \frac{6 32}{2} \leq x \leq \frac{6 32}{2}

Alternative Form

x \in [- \frac{6 32}{2}, \frac{6 32}{2}]

Show Solution