Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x∈(−∞,0)∪(6,+∞)
Evaluate
4x×x5×2(x×1)(x−6)×2>0
Remove the parentheses
4x×x5×2x×1×(x−6)×2>0
Multiply the terms
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Evaluate
4x×x5×2x×1×(x−6)×2
Rewrite the expression
4x×x5×2x(x−6)×2
Multiply the terms
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Evaluate
4×2×2
Multiply the terms
8×2
Multiply the numbers
16
16x×x5×x(x−6)
Multiply the terms with the same base by adding their exponents
16x1+5+1(x−6)
Add the numbers
16x7(x−6)
16x7(x−6)>0
Rewrite the expression
16x7(x−6)=0
Elimination the left coefficient
x7(x−6)=0
Separate the equation into 2 possible cases
x7=0x−6=0
The only way a power can be 0 is when the base equals 0
x=0x−6=0
Solve the equation
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Evaluate
x−6=0
Move the constant to the right-hand side and change its sign
x=0+6
Removing 0 doesn't change the value,so remove it from the expression
x=6
x=0x=6
Determine the test intervals using the critical values
x<00<x<6x>6
Choose a value form each interval
x1=−1x2=3x3=7
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
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Evaluate
16(−1)7(−1−6)>0
Simplify
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Evaluate
16(−1)7(−1−6)
Subtract the numbers
16(−1)7(−7)
Rewrite the expression
−16(−1)7×7
Multiply the terms
−112(−1)7
Multiply the terms
−(−112)
When there is - in front of an expression in parentheses change the sign of each term of the expression and remove the parentheses
112
112>0
Check the inequality
true
x<0 is the solutionx2=3x3=7
To determine if 0<x<6 is the solution to the inequality,test if the chosen value x=3 satisfies the initial inequality
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Evaluate
16×37(3−6)>0
Simplify
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Evaluate
16×37(3−6)
Subtract the numbers
16×37(−3)
Rewrite the expression
−16×37×3
Multiply the terms with the same base by adding their exponents
−16×37+1
Add the numbers
−16×38
Multiply the terms
−104976
−104976>0
Check the inequality
false
x<0 is the solution0<x<6 is not a solutionx3=7
To determine if x>6 is the solution to the inequality,test if the chosen value x=7 satisfies the initial inequality
More Steps

Evaluate
16×77(7−6)>0
Simplify
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Evaluate
16×77(7−6)
Subtract the numbers
16×77×1
Multiply the terms
16×77
16×77>0
Calculate
1.317669×107>0
Check the inequality
true
x<0 is the solution0<x<6 is not a solutionx>6 is the solution
Solution
x∈(−∞,0)∪(6,+∞)
Show Solution
