Question
Solve the quadratic equation
Solve by factoring
Solve using the quadratic formula
Solve by completing the square
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x1=53,x2=59
Alternative Form
x1=0.6,x2=1.8
Evaluate
5(5x−6)2−27=18
Expand the expression
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Evaluate
5(5x−6)2−27
Expand the expression
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Evaluate
5(5x−6)2
Expand the expression
5(25x2−60x+36)
Apply the distributive property
5×25x2−5×60x+5×36
Multiply the numbers
125x2−5×60x+5×36
Multiply the numbers
125x2−300x+5×36
Multiply the numbers
125x2−300x+180
125x2−300x+180−27
Subtract the numbers
125x2−300x+153
125x2−300x+153=18
Move the expression to the left side
125x2−300x+135=0
Factor the expression
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Evaluate
125x2−300x+135
Rewrite the expression
5×25x2−5×60x+5×27
Factor out 5 from the expression
5(25x2−60x+27)
Factor the expression
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Evaluate
25x2−60x+27
Rewrite the expression
25x2+(−15−45)x+27
Calculate
25x2−15x−45x+27
Rewrite the expression
5x×5x−5x×3−9×5x+9×3
Factor out 5x from the expression
5x(5x−3)−9×5x+9×3
Factor out −9 from the expression
5x(5x−3)−9(5x−3)
Factor out 5x−3 from the expression
(5x−9)(5x−3)
5(5x−9)(5x−3)
5(5x−9)(5x−3)=0
Divide the terms
(5x−9)(5x−3)=0
When the product of factors equals 0,at least one factor is 0
5x−9=05x−3=0
Solve the equation for x
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Evaluate
5x−9=0
Move the constant to the right-hand side and change its sign
5x=0+9
Removing 0 doesn't change the value,so remove it from the expression
5x=9
Divide both sides
55x=59
Divide the numbers
x=59
x=595x−3=0
Solve the equation for x
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Evaluate
5x−3=0
Move the constant to the right-hand side and change its sign
5x=0+3
Removing 0 doesn't change the value,so remove it from the expression
5x=3
Divide both sides
55x=53
Divide the numbers
x=53
x=59x=53
Solution
x1=53,x2=59
Alternative Form
x1=0.6,x2=1.8
Show Solution
