Question
Solve the equation
x1=−510log10(5),x2=0,x3=510log10(5)
Alternative Form
x1≈−0.528761,x2=0,x3≈0.528761
Evaluate
5x4=log10(5)×(x2×2)
Remove the parentheses
5x4=log10(5)×x2×2
Use the commutative property to reorder the terms
5x4=2log10(5)×x2
Add or subtract both sides
5x4−2log10(5)×x2=0
Factor the expression
x2(5x2−2log10(5))=0
Separate the equation into 2 possible cases
x2=05x2−2log10(5)=0
The only way a power can be 0 is when the base equals 0
x=05x2−2log10(5)=0
Solve the equation
More Steps

Evaluate
5x2−2log10(5)=0
Move the constant to the right-hand side and change its sign
5x2=0+2log10(5)
Add the terms
5x2=2log10(5)
Divide both sides
55x2=52log10(5)
Divide the numbers
x2=52log10(5)
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±52log10(5)
Simplify the expression
More Steps

Evaluate
52log10(5)
To take a root of a fraction,take the root of the numerator and denominator separately
52log10(5)
Multiply by the Conjugate
5×52log10(5)×5
Multiply the numbers
5×510log10(5)
When a square root of an expression is multiplied by itself,the result is that expression
510log10(5)
x=±510log10(5)
Separate the equation into 2 possible cases
x=510log10(5)x=−510log10(5)
x=0x=510log10(5)x=−510log10(5)
Solution
x1=−510log10(5),x2=0,x3=510log10(5)
Alternative Form
x1≈−0.528761,x2=0,x3≈0.528761
Show Solution
