Solve 5(x--1)-3(2x^2)=3-7x

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

x_{1} = \frac{3 - 2 3}{3}, x_{2} = \frac{3 + 2 3}{3}

Alternative Form

x_{1} \approx - 0.154701, x_{2} \approx 2.154701

Evaluate

5 (x + 1) - 3 \times 2 x^{2} = 3 - 7 x

Multiply the numbers

5 (x + 1) - 6 x^{2} = 3 - 7 x

Expand the expression

More Steps

5 x + 5 - 6 x^{2} = 3 - 7 x

Move the expression to the left side

12 x + 2 - 6 x^{2} = 0

Rewrite in standard form

- 6 x^{2} + 12 x + 2 = 0

Multiply both sides

6 x^{2} - 12 x - 2 = 0

Substitute a= 6,b= - 12 and c= - 2 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{12 \pm ( - 12 ) ^{2} - 4 \times 6 ( - 2 )}{2 \times 6}

Simplify the expression

x = \frac{12 \pm ( - 12 ) ^{2} - 4 \times 6 ( - 2 )}{12}

Simplify the expression

More Steps

x = \frac{12 \pm 192}{12}

Simplify the radical expression

More Steps

x = \frac{12 \pm 8 3}{12}

Separate the equation into 2 possible cases

x = \frac{12 + 8 3}{12} x = \frac{12 - 8 3}{12}

Simplify the expression

More Steps

x = \frac{3 + 2 3}{3} x = \frac{12 - 8 3}{12}

Simplify the expression

More Steps

x = \frac{3 + 2 3}{3} x = \frac{3 - 2 3}{3}

Solution

x_{1} = \frac{3 - 2 3}{3}, x_{2} = \frac{3 + 2 3}{3}

Alternative Form

x_{1} \approx - 0.154701, x_{2} \approx 2.154701

Show Solution