Question
Solve the equation
x=10
Evaluate
5(x−7)−12=28x−277
Move the expression to the left side
5(x−7)−12−(28x−277)=0
Subtract the terms
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Evaluate
5(x−7)−12−(28x−277)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
5(x−7)−12−28x+277
Add the numbers
5(x−7)+265−28x
5(x−7)+265−28x=0
Calculate the sum or difference
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Evaluate
5(x−7)+265−28x
Expand the expression
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Calculate
5(x−7)
Apply the distributive property
5x−5×7
Multiply the numbers
5x−35
5x−35+265−28x
Subtract the terms
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Evaluate
5x−28x
Collect like terms by calculating the sum or difference of their coefficients
(5−28)x
Subtract the numbers
−23x
−23x−35+265
Add the numbers
−23x+230
−23x+230=0
Move the constant to the right-hand side and change its sign
−23x=0−230
Removing 0 doesn't change the value,so remove it from the expression
−23x=−230
Change the signs on both sides of the equation
23x=230
Divide both sides
2323x=23230
Divide the numbers
x=23230
Solution
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Evaluate
23230
Reduce the numbers
110
Calculate
10
x=10
Show Solution

Rewrite the equation
x=10
Evaluate
5(x−7)−12=28x−277
Evaluate
More Steps

Evaluate
5(x−7)−12
Expand the expression
More Steps

Calculate
5(x−7)
Apply the distributive property
5x−5×7
Multiply the numbers
5x−35
5x−35−12
Subtract the numbers
5x−47
5x−47=28x−277
Move the variable to the left side
−23x−47=−277
Move the constant to the right side
−23x=−230
Multiply both sides
23x=230
Solution
x=10
Show Solution
