Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
x=1
Evaluate
5−2x3=4x−1
Move the expression to the left side
5−2x3−(4x−1)=0
Subtract the terms
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Evaluate
5−2x3−(4x−1)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
5−2x3−4x+1
Add the numbers
6−2x3−4x
6−2x3−4x=0
Factor the expression
2(1−x)(x2+x+3)=0
Divide both sides
(1−x)(x2+x+3)=0
Separate the equation into 2 possible cases
1−x=0x2+x+3=0
Solve the equation
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Evaluate
1−x=0
Move the constant to the right-hand side and change its sign
−x=0−1
Removing 0 doesn't change the value,so remove it from the expression
−x=−1
Change the signs on both sides of the equation
x=1
x=1x2+x+3=0
Solve the equation
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Evaluate
x2+x+3=0
Substitute a=1,b=1 and c=3 into the quadratic formula x=2a−b±b2−4ac
x=2−1±12−4×3
Simplify the expression
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Evaluate
12−4×3
1 raised to any power equals to 1
1−4×3
Multiply the numbers
1−12
Subtract the numbers
−11
x=2−1±−11
The expression is undefined in the set of real numbers
x∈/R
x=1x∈/R
Solution
x=1
Show Solution
Graph
