Solve 5h^38+3h^47

Simplify the expression

40 h^{3} + 21 h^{4}

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h^{3} (40 + 21 h)

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h_{1} = - \frac{40}{21}, h_{2} = 0

Alternative Form

h_{1} = - 1. \dot{9} 0476 \dot{1}, h_{2} = 0

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