Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
(j−5)(5j+1)
Evaluate
5j2−24j−5
Rewrite the expression
5j2+(1−25)j−5
Calculate
5j2+j−25j−5
Rewrite the expression
j×5j+j−5×5j−5
Factor out j from the expression
j(5j+1)−5×5j−5
Factor out −5 from the expression
j(5j+1)−5(5j+1)
Solution
(j−5)(5j+1)
Show Solution
Find the roots
j1=−51,j2=5
Alternative Form
j1=−0.2,j2=5
Evaluate
5j2−24j−5
To find the roots of the expression,set the expression equal to 0
5j2−24j−5=0
Factor the expression
More Steps
Evaluate
5j2−24j−5
Rewrite the expression
5j2+(1−25)j−5
Calculate
5j2+j−25j−5
Rewrite the expression
j×5j+j−5×5j−5
Factor out j from the expression
j(5j+1)−5×5j−5
Factor out −5 from the expression
j(5j+1)−5(5j+1)
Factor out 5j+1 from the expression
(j−5)(5j+1)
(j−5)(5j+1)=0
When the product of factors equals 0,at least one factor is 0
j−5=05j+1=0
Solve the equation for j
More Steps
Evaluate
j−5=0
Move the constant to the right-hand side and change its sign
j=0+5
Removing 0 doesn't change the value,so remove it from the expression
j=5
j=55j+1=0
Solve the equation for j
More Steps
Evaluate
5j+1=0
Move the constant to the right-hand side and change its sign
5j=0−1
Removing 0 doesn't change the value,so remove it from the expression
5j=−1
Divide both sides
55j=5−1
Divide the numbers
j=5−1
Use b−a=−ba=−ba to rewrite the fraction
j=−51
j=5j=−51
Solution
j1=−51,j2=5
Alternative Form
j1=−0.2,j2=5
Show Solution