Question
Factor the expression
(j−1)(5j+2)
Evaluate
5j2−3j−2
Rewrite the expression
5j2+(2−5)j−2
Calculate
5j2+2j−5j−2
Rewrite the expression
j×5j+j×2−5j−2
Factor out j from the expression
j(5j+2)−5j−2
Factor out −1 from the expression
j(5j+2)−(5j+2)
Solution
(j−1)(5j+2)
Show Solution

Find the roots
j1=−52,j2=1
Alternative Form
j1=−0.4,j2=1
Evaluate
5j2−3j−2
To find the roots of the expression,set the expression equal to 0
5j2−3j−2=0
Factor the expression
More Steps

Evaluate
5j2−3j−2
Rewrite the expression
5j2+(2−5)j−2
Calculate
5j2+2j−5j−2
Rewrite the expression
j×5j+j×2−5j−2
Factor out j from the expression
j(5j+2)−5j−2
Factor out −1 from the expression
j(5j+2)−(5j+2)
Factor out 5j+2 from the expression
(j−1)(5j+2)
(j−1)(5j+2)=0
When the product of factors equals 0,at least one factor is 0
j−1=05j+2=0
Solve the equation for j
More Steps

Evaluate
j−1=0
Move the constant to the right-hand side and change its sign
j=0+1
Removing 0 doesn't change the value,so remove it from the expression
j=1
j=15j+2=0
Solve the equation for j
More Steps

Evaluate
5j+2=0
Move the constant to the right-hand side and change its sign
5j=0−2
Removing 0 doesn't change the value,so remove it from the expression
5j=−2
Divide both sides
55j=5−2
Divide the numbers
j=5−2
Use b−a=−ba=−ba to rewrite the fraction
j=−52
j=1j=−52
Solution
j1=−52,j2=1
Alternative Form
j1=−0.4,j2=1
Show Solution
