Question
Find the roots
t1=107−1249,t2=107+1249
Alternative Form
t1≈−2.834119,t2≈4.234119
Evaluate
5t2−7t−60
To find the roots of the expression,set the expression equal to 0
5t2−7t−60=0
Substitute a=5,b=−7 and c=−60 into the quadratic formula t=2a−b±b2−4ac
t=2×57±(−7)2−4×5(−60)
Simplify the expression
t=107±(−7)2−4×5(−60)
Simplify the expression
More Steps

Evaluate
(−7)2−4×5(−60)
Multiply
More Steps

Multiply the terms
4×5(−60)
Rewrite the expression
−4×5×60
Multiply the terms
−1200
(−7)2−(−1200)
Rewrite the expression
72−(−1200)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
72+1200
Evaluate the power
49+1200
Add the numbers
1249
t=107±1249
Separate the equation into 2 possible cases
t=107+1249t=107−1249
Solution
t1=107−1249,t2=107+1249
Alternative Form
t1≈−2.834119,t2≈4.234119
Show Solution
