Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve for x
x>320
Alternative Form
x∈(320,+∞)
Evaluate
5x×x2>100
Multiply
More Steps

Evaluate
5x×x2
Multiply the terms with the same base by adding their exponents
5x1+2
Add the numbers
5x3
5x3>100
Move the expression to the left side
5x3−100>0
Rewrite the expression
5x3−100=0
Move the constant to the right-hand side and change its sign
5x3=0+100
Removing 0 doesn't change the value,so remove it from the expression
5x3=100
Divide both sides
55x3=5100
Divide the numbers
x3=5100
Divide the numbers
More Steps

Evaluate
5100
Reduce the numbers
120
Calculate
20
x3=20
Take the 3-th root on both sides of the equation
3x3=320
Calculate
x=320
Determine the test intervals using the critical values
x<320x>320
Choose a value form each interval
x1=2x2=4
To determine if x<320 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
More Steps

Evaluate
5×23>100
Multiply the terms
More Steps

Evaluate
5×23
Evaluate the power
5×8
Multiply the numbers
40
40>100
Check the inequality
false
x<320 is not a solutionx2=4
To determine if x>320 is the solution to the inequality,test if the chosen value x=4 satisfies the initial inequality
More Steps

Evaluate
5×43>100
Multiply the terms
More Steps

Evaluate
5×43
Evaluate the power
5×64
Multiply the numbers
320
320>100
Check the inequality
true
x<320 is not a solutionx>320 is the solution
Solution
x>320
Alternative Form
x∈(320,+∞)
Show Solution
