Question
Solve the equation
Solve for x
Solve for y
Solve for z
x=5y28+2z
Evaluate
5xy−2z=28
Rewrite the expression
5yx−2z=28
Move the expression to the right-hand side and change its sign
5yx=28+2z
Divide both sides
5y5yx=5y28+2z
Solution
x=5y28+2z
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Find the partial derivative
Find ∂x∂z by differentiating the equation directly
Find ∂y∂z by differentiating the equation directly
∂x∂z=25y
Evaluate
5xy−2z=28
Find ∂x∂z by taking the derivative of both sides with respect to x
∂x∂(5xy−2z)=∂x∂(28)
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂x∂(5xy)−∂x∂(2z)=∂x∂(28)
Evaluate
More Steps

Evaluate
∂x∂(5xy)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
5y×∂x∂(x)
Use ∂x∂xn=nxn−1 to find derivative
5y×1
Multiply the terms
5y
5y−∂x∂(2z)=∂x∂(28)
Evaluate
More Steps

Evaluate
∂x∂(2z)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
2×∂x∂(z)
Find the derivative
2∂x∂z
5y−2∂x∂z=∂x∂(28)
Find the partial derivative
5y−2∂x∂z=0
Move the expression to the right-hand side and change its sign
−2∂x∂z=0−5y
Removing 0 doesn't change the value,so remove it from the expression
−2∂x∂z=−5y
Change the signs on both sides of the equation
2∂x∂z=5y
Divide both sides
22∂x∂z=25y
Solution
∂x∂z=25y
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