Solve 5x^(2)-2x-1=0

Evaluate

5 x^{2} - 2 x - 1 = 0

Substitute a= 5,b= - 2 and c= - 1 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{2 \pm ( - 2 ) ^{2} - 4 \times 5 ( - 1 )}{2 \times 5}

Simplify the expression

x = \frac{2 \pm ( - 2 ) ^{2} - 4 \times 5 ( - 1 )}{10}

Simplify the expression

More Steps

x = \frac{2 \pm 24}{10}

Simplify the radical expression

More Steps

x = \frac{2 \pm 2 6}{10}

Separate the equation into 2 possible cases

x = \frac{2 + 2 6}{10} x = \frac{2 - 2 6}{10}

Simplify the expression

More Steps

x = \frac{1 + 6}{5} x = \frac{2 - 2 6}{10}

Simplify the expression

More Steps

x = \frac{1 + 6}{5} x = \frac{1 - 6}{5}

Solution

x_{1} = \frac{1 - 6}{5}, x_{2} = \frac{1 + 6}{5}

Alternative Form

x_{1} \approx - 0.289898, x_{2} \approx 0.689898

Solve the quadratic equation