Solve 5x^2 > 57 - ScanMath

Question

Solve the inequality

Solve the inequality by testing the values in the interval

Solve for x

x \in (- \infty, - \frac{285}{5}) \cup (\frac{285}{5}, + \infty)

Evaluate

5 x^{2} > 57

Move the expression to the left side

5 x^{2} - 57 > 0

Rewrite the expression

5 x^{2} - 57 = 0

Move the constant to the right-hand side and change its sign

5 x^{2} = 0 + 57

Removing 0 doesn't change the value,so remove it from the expression

5 x^{2} = 57

Divide both sides

\frac{5 x ^{2}}{5} = \frac{57}{5}

Divide the numbers

x^{2} = \frac{57}{5}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm \frac{57}{5}

Simplify the expression

More Steps

x = \pm \frac{285}{5}

Separate the equation into 2 possible cases

x = \frac{285}{5} x = - \frac{285}{5}

Determine the test intervals using the critical values

x < - \frac{285}{5} - \frac{285}{5} < x < \frac{285}{5} x > \frac{285}{5}

Choose a value form each interval

x_{1} = - 4 x_{2} = 0 x_{3} = 4

To determine if x < - \frac{285}{5} is the solution to the inequality,test if the chosen value x = - 4 satisfies the initial inequality

More Steps

x < - \frac{285}{5} is the solution x_{2} = 0 x_{3} = 4

To determine if - \frac{285}{5} < x < \frac{285}{5} is the solution to the inequality,test if the chosen value x = 0 satisfies the initial inequality

More Steps

x < - \frac{285}{5} is the solution - \frac{285}{5} < x < \frac{285}{5} is not a solution x_{3} = 4

To determine if x > \frac{285}{5} is the solution to the inequality,test if the chosen value x = 4 satisfies the initial inequality

More Steps

x < - \frac{285}{5} is the solution - \frac{285}{5} < x < \frac{285}{5} is not a solution x > \frac{285}{5} is the solution

Solution

x \in (- \infty, - \frac{285}{5}) \cup (\frac{285}{5}, + \infty)

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