Solve 5x^2-24x-5 - ScanMath

Question

Factor the expression

(x - 5) (5 x + 1)

Evaluate

5 x^{2} - 24 x - 5

Rewrite the expression

5 x^{2} + (1 - 25) x - 5

Calculate

5 x^{2} + x - 25 x - 5

Rewrite the expression

x \times 5 x + x - 5 \times 5 x - 5

Factor out x from the expression

x (5 x + 1) - 5 \times 5 x - 5

Factor out - 5 from the expression

x (5 x + 1) - 5 (5 x + 1)

Solution

(x - 5) (5 x + 1)

Show Solution

x_{1} = - \frac{1}{5}, x_{2} = 5

Alternative Form

x_{1} = - 0.2, x_{2} = 5

Evaluate

5 x^{2} - 24 x - 5

To find the roots of the expression,set the expression equal to 0

5 x^{2} - 24 x - 5 = 0

Factor the expression

More Steps

Evaluate

5 x^{2} - 24 x - 5

Rewrite the expression

5 x^{2} + (1 - 25) x - 5

Calculate

5 x^{2} + x - 25 x - 5

Rewrite the expression

x \times 5 x + x - 5 \times 5 x - 5

Factor out x from the expression

x (5 x + 1) - 5 \times 5 x - 5

Factor out - 5 from the expression

x (5 x + 1) - 5 (5 x + 1)

Factor out 5 x + 1 from the expression

(x - 5) (5 x + 1)

(x - 5) (5 x + 1) = 0

When the product of factors equals 0,at least one factor is 0

x - 5 = 0 5 x + 1 = 0

Solve the equation for x

More Steps

Evaluate

x - 5 = 0

Move the constant to the right-hand side and change its sign

x = 0 + 5

Removing 0 doesn't change the value,so remove it from the expression

x = 5

x = 5 5 x + 1 = 0

Solve the equation for x

More Steps

Evaluate

5 x + 1 = 0

Move the constant to the right-hand side and change its sign

5 x = 0 - 1

Removing 0 doesn't change the value,so remove it from the expression

5 x = - 1

Divide both sides

\frac{5 x}{5} = \frac{- 1}{5}

Divide the numbers

x = \frac{- 1}{5}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

x = - \frac{1}{5}

x = 5 x = - \frac{1}{5}

Solution

x_{1} = - \frac{1}{5}, x_{2} = 5

Alternative Form

x_{1} = - 0.2, x_{2} = 5

Show Solution