Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
x1=0,x2=1625
Alternative Form
x1=0,x2≈0.030864
Evaluate
5x2−27x3×6=0
Multiply the terms
5x2−162x3=0
Factor the expression
x2(5−162x)=0
Separate the equation into 2 possible cases
x2=05−162x=0
The only way a power can be 0 is when the base equals 0
x=05−162x=0
Solve the equation
More Steps
Evaluate
5−162x=0
Move the constant to the right-hand side and change its sign
−162x=0−5
Removing 0 doesn't change the value,so remove it from the expression
−162x=−5
Change the signs on both sides of the equation
162x=5
Divide both sides
162162x=1625
Divide the numbers
x=1625
x=0x=1625
Solution
x1=0,x2=1625
Alternative Form
x1=0,x2≈0.030864
Show Solution
Graph
