Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
x1=0,x2=2165
Alternative Form
x1=0,x2=0.0231˙48˙
Evaluate
5x2−36x3×6=0
Multiply the terms
5x2−216x3=0
Factor the expression
x2(5−216x)=0
Separate the equation into 2 possible cases
x2=05−216x=0
The only way a power can be 0 is when the base equals 0
x=05−216x=0
Solve the equation
More Steps
Evaluate
5−216x=0
Move the constant to the right-hand side and change its sign
−216x=0−5
Removing 0 doesn't change the value,so remove it from the expression
−216x=−5
Change the signs on both sides of the equation
216x=5
Divide both sides
216216x=2165
Divide the numbers
x=2165
x=0x=2165
Solution
x1=0,x2=2165
Alternative Form
x1=0,x2=0.0231˙48˙
Show Solution
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