Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
(x+1)(5x2+7)
Evaluate
5x3+7x+5x2+7
Rewrite the expression
x×5x2+x×7+5x2+7
Factor out x from the expression
x(5x2+7)+5x2+7
Solution
(x+1)(5x2+7)
Show Solution
Find the roots
x1=−535i,x2=535i,x3=−1
Alternative Form
x1≈−1.183216i,x2≈1.183216i,x3=−1
Evaluate
5x3+7x+5x2+7
To find the roots of the expression,set the expression equal to 0
5x3+7x+5x2+7=0
Factor the expression
(x+1)(5x2+7)=0
Separate the equation into 2 possible cases
x+1=05x2+7=0
Solve the equation
More Steps
Evaluate
x+1=0
Move the constant to the right-hand side and change its sign
x=0−1
Removing 0 doesn't change the value,so remove it from the expression
x=−1
x=−15x2+7=0
Solve the equation
More Steps
Evaluate
5x2+7=0
Move the constant to the right-hand side and change its sign
5x2=0−7
Removing 0 doesn't change the value,so remove it from the expression
5x2=−7
Divide both sides
55x2=5−7
Divide the numbers
x2=5−7
Use b−a=−ba=−ba to rewrite the fraction
x2=−57
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±−57
Simplify the expression
More Steps
Evaluate
−57
Evaluate the power
57×−1
Evaluate the power
57×i
Evaluate the power
535i
x=±535i
Separate the equation into 2 possible cases
x=535ix=−535i
x=−1x=535ix=−535i
Solution
x1=−535i,x2=535i,x3=−1
Alternative Form
x1≈−1.183216i,x2≈1.183216i,x3=−1
Show Solution