Question
Solve the equation
a=1
Evaluate
6(3a+1)−30=3(2a−4)
Calculate
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Evaluate
6(3a+1)−30
Expand the expression
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Calculate
6(3a+1)
Apply the distributive property
6×3a+6×1
Multiply the numbers
18a+6×1
Any expression multiplied by 1 remains the same
18a+6
18a+6−30
Subtract the numbers
18a−24
18a−24=3(2a−4)
Calculate
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Evaluate
3(2a−4)
Apply the distributive property
3×2a−3×4
Multiply the numbers
6a−3×4
Multiply the numbers
6a−12
18a−24=6a−12
Move the expression to the left side
18a−24−(6a−12)=0
Calculate
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Add the terms
18a−24−(6a−12)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
18a−24−6a+12
Subtract the terms
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Evaluate
18a−6a
Collect like terms by calculating the sum or difference of their coefficients
(18−6)a
Subtract the numbers
12a
12a−24+12
Add the numbers
12a−12
12a−12=0
Move the constant to the right-hand side and change its sign
12a=0+12
Removing 0 doesn't change the value,so remove it from the expression
12a=12
Divide both sides
1212a=1212
Divide the numbers
a=1212
Solution
More Steps

Evaluate
1212
Reduce the numbers
11
Calculate
1
a=1
Show Solution
