Solve 6(j-10)=-8j 10j

Question

6 (j - 10) = - 8 j \times 10 j

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

j_{1} = - \frac{3 + 4809}{80}, j_{2} = \frac{- 3 + 4809}{80}

Alternative Form

j_{1} \approx - 0.904337, j_{2} \approx 0.829337

Evaluate

6 (j - 10) = - 8 j \times 10 j

Multiply

More Steps

6 (j - 10) = - 80 j^{2}

Swap the sides

- 80 j^{2} = 6 (j - 10)

Expand the expression

More Steps

- 80 j^{2} = 6 j - 60

Move the expression to the left side

- 80 j^{2} - 6 j + 60 = 0

Multiply both sides

80 j^{2} + 6 j - 60 = 0

Substitute a= 80,b= 6 and c= - 60 into the quadratic formula j = \frac{- b \pm b ^{2} - 4 a c}{2 a}

j = \frac{- 6 \pm 6 ^{2} - 4 \times 80 ( - 60 )}{2 \times 80}

Simplify the expression

j = \frac{- 6 \pm 6 ^{2} - 4 \times 80 ( - 60 )}{160}

Simplify the expression

More Steps

j = \frac{- 6 \pm 19236}{160}

Simplify the radical expression

More Steps

j = \frac{- 6 \pm 2 4809}{160}

Separate the equation into 2 possible cases

j = \frac{- 6 + 2 4809}{160} j = \frac{- 6 - 2 4809}{160}

Simplify the expression

More Steps

j = \frac{- 3 + 4809}{80} j = \frac{- 6 - 2 4809}{160}

Simplify the expression

More Steps

j = \frac{- 3 + 4809}{80} j = - \frac{3 + 4809}{80}

Solution

j_{1} = - \frac{3 + 4809}{80}, j_{2} = \frac{- 3 + 4809}{80}

Alternative Form

j_{1} \approx - 0.904337, j_{2} \approx 0.829337

Show Solution