Solve 6-(1-x) 5x =0

Evaluate

6 - (1 - x) \times 5 x = 0

Multiply the first two terms

6 - 5 (1 - x) x = 0

Expand the expression

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6 - 5 x + 5 x^{2} = 0

Rewrite in standard form

5 x^{2} - 5 x + 6 = 0

Substitute a= 5,b= - 5 and c= 6 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{5 \pm ( - 5 ) ^{2} - 4 \times 5 \times 6}{2 \times 5}

Simplify the expression

x = \frac{5 \pm ( - 5 ) ^{2} - 4 \times 5 \times 6}{10}

Simplify the expression

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x = \frac{5 \pm - 95}{10}

Simplify the radical expression

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x = \frac{5 \pm 95 \times i}{10}

Separate the equation into 2 possible cases

x = \frac{5 + 95 \times i}{10} x = \frac{5 - 95 \times i}{10}

Simplify the expression

x = \frac{1}{2} + \frac{95}{10} i x = \frac{5 - 95 \times i}{10}

Simplify the expression

x = \frac{1}{2} + \frac{95}{10} i x = \frac{1}{2} - \frac{95}{10} i

Solution

x_{1} = \frac{1}{2} - \frac{95}{10} i, x_{2} = \frac{1}{2} + \frac{95}{10} i

Alternative Form

x_{1} \approx 0.5 - 0.974679 i, x_{2} \approx 0.5 + 0.974679 i

Solve the equation(The real numbers system)