Solve 6-41l[l] - ScanMath

Question

Simplify the expression

6 - 41 l^{2}

Evaluate

6 - 41 l \times l

Solution

6 - 41 l^{2}

Show Solution

l_{1} = - \frac{246}{41}, l_{2} = \frac{246}{41}

Alternative Form

l_{1} \approx - 0.382546, l_{2} \approx 0.382546

Evaluate

6 - 41 l \times l

To find the roots of the expression,set the expression equal to 0

6 - 41 l \times l = 0

Multiply the terms

6 - 41 l^{2} = 0

Move the constant to the right-hand side and change its sign

- 41 l^{2} = 0 - 6

Removing 0 doesn't change the value,so remove it from the expression

- 41 l^{2} = - 6

Change the signs on both sides of the equation

41 l^{2} = 6

Divide both sides

\frac{41 l ^{2}}{41} = \frac{6}{41}

Divide the numbers

l^{2} = \frac{6}{41}

Take the root of both sides of the equation and remember to use both positive and negative roots

l = \pm \frac{6}{41}

Simplify the expression

More Steps

Evaluate

\frac{6}{41}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{6}{41}

Multiply by the Conjugate

\frac{6 \times 41}{41 \times 41}

Multiply the numbers

More Steps

Evaluate

6 \times 41

The product of roots with the same index is equal to the root of the product

6 \times 41

Calculate the product

246

\frac{246}{41 \times 41}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{246}{41}

l = \pm \frac{246}{41}

Separate the equation into 2 possible cases

l = \frac{246}{41} l = - \frac{246}{41}

Solution

l_{1} = - \frac{246}{41}, l_{2} = \frac{246}{41}

Alternative Form

l_{1} \approx - 0.382546, l_{2} \approx 0.382546

Show Solution