Solve 68=-7(t-12) 5t - ScanMath

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Type your math problem... 68=-7(t-12) 5t

Question

Solve the quadratic equation

Solve using the quadratic formula

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Solve by completing the square

Solve using the PQ formula

t_{1} = \frac{210 - 2 10430}{35}, t_{2} = \frac{210 + 2 10430}{35}

Alternative Form

t_{1} \approx 0.16415, t_{2} \approx 11.83585

Evaluate

68 = - 7 (t - 12) \times 5 t

Multiply

More Steps

68 = - 35 t (t - 12)

Swap the sides

- 35 t (t - 12) = 68

Expand the expression

More Steps

- 35 t^{2} + 420 t = 68

Move the expression to the left side

- 35 t^{2} + 420 t - 68 = 0

Multiply both sides

35 t^{2} - 420 t + 68 = 0

Substitute a= 35,b= - 420 and c= 68 into the quadratic formula t = \frac{- b \pm b ^{2} - 4 a c}{2 a}

t = \frac{420 \pm ( - 420 ) ^{2} - 4 \times 35 \times 68}{2 \times 35}

Simplify the expression

t = \frac{420 \pm ( - 420 ) ^{2} - 4 \times 35 \times 68}{70}

Simplify the expression

More Steps

t = \frac{420 \pm 42 0 ^{2} - 9520}{70}

Simplify the radical expression

More Steps

t = \frac{420 \pm 4 10430}{70}

Separate the equation into 2 possible cases

t = \frac{420 + 4 10430}{70} t = \frac{420 - 4 10430}{70}

Simplify the expression

More Steps

t = \frac{210 + 2 10430}{35} t = \frac{420 - 4 10430}{70}

Simplify the expression

More Steps

t = \frac{210 + 2 10430}{35} t = \frac{210 - 2 10430}{35}

Solution

t_{1} = \frac{210 - 2 10430}{35}, t_{2} = \frac{210 + 2 10430}{35}

Alternative Form

t_{1} \approx 0.16415, t_{2} \approx 11.83585

Show Solution

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