Question
Factor the expression
(2x−3)(3x+1)
Evaluate
6x2−3−7x
Reorder the terms
6x2−7x−3
Rewrite the expression
6x2+(2−9)x−3
Calculate
6x2+2x−9x−3
Rewrite the expression
2x×3x+2x−3×3x−3
Factor out 2x from the expression
2x(3x+1)−3×3x−3
Factor out −3 from the expression
2x(3x+1)−3(3x+1)
Solution
(2x−3)(3x+1)
Show Solution

Find the roots
x1=−31,x2=23
Alternative Form
x1=−0.3˙,x2=1.5
Evaluate
6x2−3−7x
To find the roots of the expression,set the expression equal to 0
6x2−3−7x=0
Factor the expression
More Steps

Evaluate
6x2−3−7x
Reorder the terms
6x2−7x−3
Rewrite the expression
6x2+(2−9)x−3
Calculate
6x2+2x−9x−3
Rewrite the expression
2x×3x+2x−3×3x−3
Factor out 2x from the expression
2x(3x+1)−3×3x−3
Factor out −3 from the expression
2x(3x+1)−3(3x+1)
Factor out 3x+1 from the expression
(2x−3)(3x+1)
(2x−3)(3x+1)=0
When the product of factors equals 0,at least one factor is 0
2x−3=03x+1=0
Solve the equation for x
More Steps

Evaluate
2x−3=0
Move the constant to the right-hand side and change its sign
2x=0+3
Removing 0 doesn't change the value,so remove it from the expression
2x=3
Divide both sides
22x=23
Divide the numbers
x=23
x=233x+1=0
Solve the equation for x
More Steps

Evaluate
3x+1=0
Move the constant to the right-hand side and change its sign
3x=0−1
Removing 0 doesn't change the value,so remove it from the expression
3x=−1
Divide both sides
33x=3−1
Divide the numbers
x=3−1
Use b−a=−ba=−ba to rewrite the fraction
x=−31
x=23x=−31
Solution
x1=−31,x2=23
Alternative Form
x1=−0.3˙,x2=1.5
Show Solution
