Question
Factor the expression
(2x+1)(3x−2)
Evaluate
6x2−x−2
Rewrite the expression
6x2+(−4+3)x−2
Calculate
6x2−4x+3x−2
Rewrite the expression
2x×3x−2x×2+3x−2
Factor out 2x from the expression
2x(3x−2)+3x−2
Solution
(2x+1)(3x−2)
Show Solution

Find the roots
x1=−21,x2=32
Alternative Form
x1=−0.5,x2=0.6˙
Evaluate
6x2−x−2
To find the roots of the expression,set the expression equal to 0
6x2−x−2=0
Factor the expression
More Steps

Evaluate
6x2−x−2
Rewrite the expression
6x2+(−4+3)x−2
Calculate
6x2−4x+3x−2
Rewrite the expression
2x×3x−2x×2+3x−2
Factor out 2x from the expression
2x(3x−2)+3x−2
Factor out 3x−2 from the expression
(2x+1)(3x−2)
(2x+1)(3x−2)=0
When the product of factors equals 0,at least one factor is 0
2x+1=03x−2=0
Solve the equation for x
More Steps

Evaluate
2x+1=0
Move the constant to the right-hand side and change its sign
2x=0−1
Removing 0 doesn't change the value,so remove it from the expression
2x=−1
Divide both sides
22x=2−1
Divide the numbers
x=2−1
Use b−a=−ba=−ba to rewrite the fraction
x=−21
x=−213x−2=0
Solve the equation for x
More Steps

Evaluate
3x−2=0
Move the constant to the right-hand side and change its sign
3x=0+2
Removing 0 doesn't change the value,so remove it from the expression
3x=2
Divide both sides
33x=32
Divide the numbers
x=32
x=−21x=32
Solution
x1=−21,x2=32
Alternative Form
x1=−0.5,x2=0.6˙
Show Solution
