Solve 7(4x-3) 3(6-5x)=4-(24x)

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

x_{1} = \frac{843 - 68889}{840}, x_{2} = \frac{843 + 68889}{840}

Alternative Form

x_{1} \approx 0.691111, x_{2} \approx 1.316032

Evaluate

7 (4 x - 3) \times 3 (6 - 5 x) = 4 - 24 x

Multiply the terms

21 (4 x - 3) (6 - 5 x) = 4 - 24 x

Expand the expression

More Steps

819 x - 420 x^{2} - 378 = 4 - 24 x

Move the expression to the left side

843 x - 420 x^{2} - 382 = 0

Rewrite in standard form

- 420 x^{2} + 843 x - 382 = 0

Multiply both sides

420 x^{2} - 843 x + 382 = 0

Substitute a= 420,b= - 843 and c= 382 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{843 \pm ( - 843 ) ^{2} - 4 \times 420 \times 382}{2 \times 420}

Simplify the expression

x = \frac{843 \pm ( - 843 ) ^{2} - 4 \times 420 \times 382}{840}

Simplify the expression

More Steps

x = \frac{843 \pm 84 3 ^{2} - 641760}{840}

Simplify the radical expression

x = \frac{843 \pm 68889}{840}

Separate the equation into 2 possible cases

x = \frac{843 + 68889}{840} x = \frac{843 - 68889}{840}

Solution

x_{1} = \frac{843 - 68889}{840}, x_{2} = \frac{843 + 68889}{840}

Alternative Form

x_{1} \approx 0.691111, x_{2} \approx 1.316032

Show Solution