Solve 737-7k^2 - ScanMath

Question

Find the roots

k_{1} = - \frac{5159}{7}, k_{2} = \frac{5159}{7}

Alternative Form

k_{1} \approx - 10.260883, k_{2} \approx 10.260883

Evaluate

737 - 7 k^{2}

To find the roots of the expression,set the expression equal to 0

737 - 7 k^{2} = 0

Move the constant to the right-hand side and change its sign

- 7 k^{2} = 0 - 737

Removing 0 doesn't change the value,so remove it from the expression

- 7 k^{2} = - 737

Change the signs on both sides of the equation

7 k^{2} = 737

Divide both sides

\frac{7 k ^{2}}{7} = \frac{737}{7}

Divide the numbers

k^{2} = \frac{737}{7}

Take the root of both sides of the equation and remember to use both positive and negative roots

k = \pm \frac{737}{7}

Simplify the expression

More Steps

Evaluate

\frac{737}{7}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{737}{7}

Multiply by the Conjugate

\frac{737 \times 7}{7 \times 7}

Multiply the numbers

More Steps

Evaluate

737 \times 7

The product of roots with the same index is equal to the root of the product

737 \times 7

Calculate the product

5159

\frac{5159}{7 \times 7}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{5159}{7}

k = \pm \frac{5159}{7}

Separate the equation into 2 possible cases

k = \frac{5159}{7} k = - \frac{5159}{7}

Solution

k_{1} = - \frac{5159}{7}, k_{2} = \frac{5159}{7}

Alternative Form

k_{1} \approx - 10.260883, k_{2} \approx 10.260883

Show Solution