Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
q∈(−∞,−549625)∪(0,549625)
Evaluate
7q×11>5q5
Multiply the terms
77q>5q5
Move the expression to the left side
77q−5q5>0
Rewrite the expression
77q−5q5=0
Factor the expression
q(77−5q4)=0
Separate the equation into 2 possible cases
q=077−5q4=0
Solve the equation
More Steps

Evaluate
77−5q4=0
Move the constant to the right-hand side and change its sign
−5q4=0−77
Removing 0 doesn't change the value,so remove it from the expression
−5q4=−77
Change the signs on both sides of the equation
5q4=77
Divide both sides
55q4=577
Divide the numbers
q4=577
Take the root of both sides of the equation and remember to use both positive and negative roots
q=±4577
Simplify the expression
More Steps

Evaluate
4577
To take a root of a fraction,take the root of the numerator and denominator separately
45477
Multiply by the Conjugate
45×453477×453
Simplify
45×453477×4125
Multiply the numbers
45×45349625
Multiply the numbers
549625
q=±549625
Separate the equation into 2 possible cases
q=549625q=−549625
q=0q=549625q=−549625
Determine the test intervals using the critical values
q<−549625−549625<q<00<q<549625q>549625
Choose a value form each interval
q1=−3q2=−1q3=1q4=3
To determine if q<−549625 is the solution to the inequality,test if the chosen value q=−3 satisfies the initial inequality
More Steps

Evaluate
77(−3)>5(−3)5
Multiply the numbers
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Evaluate
77(−3)
Multiplying or dividing an odd number of negative terms equals a negative
−77×3
Multiply the numbers
−231
−231>5(−3)5
Multiply the terms
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Evaluate
5(−3)5
Evaluate the power
5(−243)
Multiply the numbers
−1215
−231>−1215
Check the inequality
true
q<−549625 is the solutionq2=−1q3=1q4=3
To determine if −549625<q<0 is the solution to the inequality,test if the chosen value q=−1 satisfies the initial inequality
More Steps

Evaluate
77(−1)>5(−1)5
Simplify
−77>5(−1)5
Multiply the terms
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Evaluate
5(−1)5
Evaluate the power
5(−1)
Multiply the numbers
−5
−77>−5
Check the inequality
false
q<−549625 is the solution−549625<q<0 is not a solutionq3=1q4=3
To determine if 0<q<549625 is the solution to the inequality,test if the chosen value q=1 satisfies the initial inequality
More Steps

Evaluate
77×1>5×15
Any expression multiplied by 1 remains the same
77>5×15
Simplify
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Evaluate
5×15
1 raised to any power equals to 1
5×1
Any expression multiplied by 1 remains the same
5
77>5
Check the inequality
true
q<−549625 is the solution−549625<q<0 is not a solution0<q<549625 is the solutionq4=3
To determine if q>549625 is the solution to the inequality,test if the chosen value q=3 satisfies the initial inequality
More Steps

Evaluate
77×3>5×35
Multiply the numbers
231>5×35
Multiply the terms
More Steps

Evaluate
5×35
Evaluate the power
5×243
Multiply the numbers
1215
231>1215
Check the inequality
false
q<−549625 is the solution−549625<q<0 is not a solution0<q<549625 is the solutionq>549625 is not a solution
Solution
q∈(−∞,−549625)∪(0,549625)
Show Solution
