Solve 7x^2+42x+35/7x+7

Evaluate

7 x^{2} + 42 x + \frac{35}{7} x + 7

To find the roots of the expression,set the expression equal to 0

7 x^{2} + 42 x + \frac{35}{7} x + 7 = 0

Divide the terms

More Steps

7 x^{2} + 42 x + 5 x + 7 = 0

Add the terms

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7 x^{2} + 47 x + 7 = 0

Substitute a= 7,b= 47 and c= 7 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{- 47 \pm 4 7 ^{2} - 4 \times 7 \times 7}{2 \times 7}

Simplify the expression

x = \frac{- 47 \pm 4 7 ^{2} - 4 \times 7 \times 7}{14}

Simplify the expression

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x = \frac{- 47 \pm 2013}{14}

Separate the equation into 2 possible cases

x = \frac{- 47 + 2013}{14} x = \frac{- 47 - 2013}{14}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

x = \frac{- 47 + 2013}{14} x = - \frac{47 + 2013}{14}

Solution

x_{1} = - \frac{47 + 2013}{14}, x_{2} = \frac{- 47 + 2013}{14}

Alternative Form

x_{1} \approx - 6.561891, x_{2} \approx - 0.152395

Simplify the expression