Solve 7x^2-22x-10

Question

Find the roots

x_{1} = \frac{11 - 191}{7}, x_{2} = \frac{11 + 191}{7}

Alternative Form

x_{1} \approx - 0.402896, x_{2} \approx 3.545754

Evaluate

7 x^{2} - 22 x - 10

To find the roots of the expression,set the expression equal to 0

7 x^{2} - 22 x - 10 = 0

Substitute a= 7,b= - 22 and c= - 10 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{22 \pm ( - 22 ) ^{2} - 4 \times 7 ( - 10 )}{2 \times 7}

Simplify the expression

x = \frac{22 \pm ( - 22 ) ^{2} - 4 \times 7 ( - 10 )}{14}

Simplify the expression

More Steps

x = \frac{22 \pm 764}{14}

Simplify the radical expression

More Steps

x = \frac{22 \pm 2 191}{14}

Separate the equation into 2 possible cases

x = \frac{22 + 2 191}{14} x = \frac{22 - 2 191}{14}

Simplify the expression

More Steps

x = \frac{11 + 191}{7} x = \frac{22 - 2 191}{14}

Simplify the expression

More Steps

x = \frac{11 + 191}{7} x = \frac{11 - 191}{7}

Solution

x_{1} = \frac{11 - 191}{7}, x_{2} = \frac{11 + 191}{7}

Alternative Form

x_{1} \approx - 0.402896, x_{2} \approx 3.545754

Show Solution