Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
214x3−x5
Evaluate
7x3−2x2x3
Multiply the terms
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Multiply the terms
2x2x3
Multiply the terms
2x2×x3
Multiply the terms
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Evaluate
x2×x3
Use the product rule an×am=an+m to simplify the expression
x2+3
Add the numbers
x5
2x5
7x3−2x5
Reduce fractions to a common denominator
27x3×2−2x5
Write all numerators above the common denominator
27x3×2−x5
Solution
214x3−x5
Show Solution
Find the roots
x1=−14,x2=0,x3=14
Alternative Form
x1≈−3.741657,x2=0,x3≈3.741657
Evaluate
7x3−2x2x3
To find the roots of the expression,set the expression equal to 0
7x3−2x2x3=0
Multiply the terms
More Steps
Multiply the terms
2x2x3
Multiply the terms
2x2×x3
Multiply the terms
More Steps
Evaluate
x2×x3
Use the product rule an×am=an+m to simplify the expression
x2+3
Add the numbers
x5
2x5
7x3−2x5=0
Subtract the terms
More Steps
Simplify
7x3−2x5
Reduce fractions to a common denominator
27x3×2−2x5
Write all numerators above the common denominator
27x3×2−x5
Multiply the terms
214x3−x5
214x3−x5=0
Simplify
14x3−x5=0
Factor the expression
x3(14−x2)=0
Separate the equation into 2 possible cases
x3=014−x2=0
The only way a power can be 0 is when the base equals 0
x=014−x2=0
Solve the equation
More Steps
Evaluate
14−x2=0
Move the constant to the right-hand side and change its sign
−x2=0−14
Removing 0 doesn't change the value,so remove it from the expression
−x2=−14
Change the signs on both sides of the equation
x2=14
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±14
Separate the equation into 2 possible cases
x=14x=−14
x=0x=14x=−14
Solution
x1=−14,x2=0,x3=14
Alternative Form
x1≈−3.741657,x2=0,x3≈3.741657
Show Solution